Electrolysis of dilute sodium chloride solution | Electrolysis of concentrated sodium chloride solution | ||
At anode : | Anions : OH- and Cl- OH- ions are selectively discharge according to the position of ions in the Electrochemical Series, ES. Gas bubbles are formed which lighted up a glowing wooden splinter. This gas is oxygen. 4OH- ---> 2 H2O + O2 + 4e | At anode : | Anions : OH- and Cl- Cl- ions are discharged instead of OH- because of their higher concentration in the electrolyte. A greenish-yellow gas with a pungent and choking smell is released. The gas turns the blue litmus paper red and then white. 2Cl- ---> Cl2 + 2e |
At cathode: | Cations : H+ dan Na+ H+ ions are selectively discharge according to the position of ions in the ES. Gas bubbles are formed. When a lighted wooden splinter is placed near the mouth of the test tube, a ‘pop’ sound is produced. Hydrogen gas is produced 2H+ + 2e ---> H2 | At cathode: | Cations : H+ dan K+ H+ ions are selectively discharge according to the position of ions in the ES. Gas bubbles are formed. When a lighted wooden splinter is placed near the mouth of the test tube, a ‘pop’ sound is produced. Hydrogen gas is produced 2H+ + 2e ---> H2 |
Pages
▼
Sorry sir..if 0.5M NaCl is considered as concentrated or dilute? We followed electrochemical series or select higher concentrated ion for 0.5M NaCl? OH- or Cl- will be selected? Thank you sir.
ReplyDeleteI think Cl- will be chosen because it can easily discharge compare to OH-
Deleteah boy please dont call me sir!
ReplyDeletegood job
ReplyDeleteHai cikgu wong, may i ask for the overall equation?
ReplyDelete