**Displacement-Time Graph:**- Gradient of the graph is equal to velocity
- Gradient = 0 , velocity = 0.
- Gradient is negative and constant, hence velocity is uniform and in opposite direction.
- Gradient is increasing, hence velocity is increasing.

__Velocity-Time Graph:__- The gradient of the velocity-time graph gives acceleration.
- Gradient = 0, hence velocity is constant but acceleration = 0.
- The area below the velocity-time graph gives a value of the object's displacement.

**Click on the diagram below to play!**
## 6 comments:

Cikgu Wong, can you help me to solve this question.

In emergency stop, a driver applies the breaks in a car travelling at 24 ms-1. The car stops after travelling 19.2m while braking. Calculate the average acceleration of the car during braking?

Initial velocity, u = 24

Final velocity, v = 0

Total distance, s = 19.2

Use V2= U2 + 2as formula

0 = 576 + 2a(19.2)

a = -576/19.2 = 30 ms-2

Thank you cikgu wong

im always confuse when i want to use the formula..which formula shouls i use .can you help me and teach me how to use formula based on the question

cikgu wong , why don't you just use this formula , v-u/t , for the first question in the comments ?

Manisha, it is because, there is no time required in the question. so you cannot use the formula v-u/t.

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